WVO titration testing...
#1
WVO titration testing...
Lets see who can help me with this! LOL!
OK, so I am in the process of completing Titration testing. Here is a couple problems I am having, and maybe I am just not catching it. I caught some tables to do the testing, but it is for much smaller amounts (400ML) and what I need to know, is how do I increase my measurements for larger quantities for processing. Any tables out there for conversion that someone uses?
Second, everything I am finding for my titration testing, is using KoOH and not NoOH. If I am using NoOH for my processing, mow much difference between the math for it as compared to the KoOH amounts?
Any input and help would be wonderful!
OK, so I am in the process of completing Titration testing. Here is a couple problems I am having, and maybe I am just not catching it. I caught some tables to do the testing, but it is for much smaller amounts (400ML) and what I need to know, is how do I increase my measurements for larger quantities for processing. Any tables out there for conversion that someone uses?
Second, everything I am finding for my titration testing, is using KoOH and not NoOH. If I am using NoOH for my processing, mow much difference between the math for it as compared to the KoOH amounts?
Any input and help would be wonderful!
#2
#3
When performing a titration, (either with KOH or NaOH), a small sample size is the intention (I titrate only 1 mL of waste oil). But the important number is the volume of catalyst(KOH or NaOH) that is used to neutralize your sample. That number is your "BASE" number and is then modified according to the type of catalyst.
For example: If I use 4 ml of my titration solution to neutralize my oil, my BASE number is 4. Because I am using NaOH, I add 5.5 to the 4 = 9.5
That 9.5 has the units of grams NaOH per liter of WVO (grams/Liter). If you have 100 liters of WVO then 100 x 9.5 = 950 grams of NaOH that must be added to your methanol.
Good luck.
For example: If I use 4 ml of my titration solution to neutralize my oil, my BASE number is 4. Because I am using NaOH, I add 5.5 to the 4 = 9.5
That 9.5 has the units of grams NaOH per liter of WVO (grams/Liter). If you have 100 liters of WVO then 100 x 9.5 = 950 grams of NaOH that must be added to your methanol.
Good luck.
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