If you bore a standard 302 block .30 over...is it a 306?

If not, then what size is it (in cubic inches)?

Thanks!
Scott

 

Yes.. it's 306 cu. in.

 

Is there a chart or formula somewhere to determine this? The guy who is disputing this will require some solid evidence....

TIA,
Scott

 

Engine Volume:

Bore Area (Pi R^2) * Stroke * Cylinders

302:
4.0" Bore, 3.0" Stroke

Bore Area = 2^2*Pi = 12.5664

12.5664 * 3 * 8 = 301.594

Bored .30 Over:

(2.15^2 * Pi) * 3 * 8 = 348.528

But, I am guessing you really meant .030 over:
(2.015^2 * Pi) * 3 * 8 = 306.134

Unless I am not understanding what you mean by .30 over then that would be a 349.

Calvin

 

yes...my bad...I meant .030 over.

Thanks!!!

Scott

 

What would a 460 bored .060 over equate to?

TIA,
Scott

 

Stock 460:
Bore - 4.36
Stroke - 3.85

Bored .060 over:
Bore - 4.42

(2.21^2 * Pi) * 3.85 * 8 = 472.592 (472 or 473 - your choice)

Calvin

 

Here ya go: http://www.wallaceracing.com/Calculators.htm

Pete

 

Thanks Guys!

Scott

 

The other displacement formula is Bore x bore x stroke x .7854 x #of cylinders

 

Cool!

Thanks!!!

 

here is a calculator Calculate Cubic Inch Displacement

 

This is why Algebra Class was so important

 

put the bore into the calculator (4.030 for a 302 .030 over). Than enter stroke. In my case I’m using a 347 stroker kit. I think that is a stroke of 3.40. So a oversized bore of 4.030 and a stroke of 3.40 = 347 ci
my figures may be wrong, but that’s how you do it



QUOTE=baddad457;19592202]This is why Algebra Class was so important [/QUOTE]

 

And thanks for answering that 13 years after it was asked.